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发表于 2007-12-18 08:45:54 | 显示全部楼层 |阅读模式

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Estimating the Connection Inductance of a Decoupling Capacitor

The equivalent series inductance (ESL) of a capacitor is often the limiting factor of a decoupling capacitor's effectiveness. By estimating the ESL, the efficacy of a decoupling strategy can be determined. The following outlines a method by which the connection inductance of a variety of decoupling capacitors can be estimated.

Step 1: Identify the Loop

The first step in estimating the inductance of a decoupling capacitor is to identify the decoupling current loop. Two cases will be considered, decoupling capacitors on boards with power routed on traces, and decoupling capacitors on boards with power and return planes.

A. Geometries where power is routed on traces
The current loop will consist of the path between the decoupling capacitor and the device that draws charge from the capacitor. In the figure shown below, the current path is shown in red.
 
IC Decap Current Loop
B. Decoupling capacitors connected to power planes
The current loop in this configuration will start at the decoupling capacitor, go through a via to one of the power planes, then from one power plane to the other, and finally through a via back to the capacitor. The impedance of the path between the power and return planes, Zboard, is not normally considered to be part of the connection inductance. Zboard can be calculated independent of the inductance of the portion of the loop above the planes. The impedance of the connection to the planes is then given by,

Zconn = jwL + Zboard

where L is the inductance of the current path above the power planes. This path is shown in red in the figure below.

IC Decap Current Loop
Step 2: Identify an Equivalent Geometry

To estimate the inductance for decoupling capacitors, the inductance of an equivalent geometry will be used. This simplification will allow us to use simple closed-form expressions to calculate the inductance.

A. Decoupling capacitors where power is routed on traces
Rectangular Loop
If the decoupling current loop is short (w<5h), then use the closed-form expression for a rectangular loop to calculate the inductance.
http://www.cvel.clemson& ... ectgl.html.
 
Rectangular Loop
Long Rectangular Loop (w>5h)
If the decoupling current loop is long (w>5h), then use the expression for the inductance per unit length of two wires and multiple by the length of the loop (w) to calculate the inductance.
http://www.cvel.clemson& ... wire2.html.
 
Wire Pair Cross-Section
B. Decoupling capacitors connected to power planes
Rectangular Loop above a Plane
If the decoupling loop is short (w<5h), use the closed-form expression for a rectangular loop with the parameter 'h' equal to 2h1, and then divide the calculated inductance in half. This inductance will be the inductance Labove.
http://www.cvel.clemson& ... ectgl.html.
 
Rectangular Loop Above Ground Plane
Long Rectangular Loop above a Plane (w>5h)
If the decoupling current loop is long (w>5h), use the expression for the inductance per unit length of a wire above a ground plane and multiply by the length of the loop (w). This inductance will be the inductance Labove.
http://www.cvel.clemson& ... -wire.html.
 
Wire Above Ground Plane
Step 3: Estimating the parameters of the closed-form inductance calculations
A. Estimating loop width 'w'
The loop width 'w' is the distance over which the current follows through the capacitor. A few examples are shown below.
 
Capacitor Trace-Via Examples
B. Estimating loop height 'h'
The height of the loop 'h' for a capacitor attached to power planes would be approximately half the height of the decoupling capacitor plus the distance between the capacitor and the closest power plane.
 
Capacitor connected to power planes
C. Estimating wire radius 'a'
The equivalent wire radius of a decoupling capacitor or flat trace can be estimated as 1/4th the width of the capacitor package or trace. Of course, most connections consist of vias, traces, pads and capacitor packages that have different equivalent wire radii. A worst case estimate of the connection inductance is obtained by using the smallest equivalent radius.
 
Flat and Round Wire Cross-Sections
Example 1: PCB Without Power Planes

Calculate the connection inductance for the capacitor connected to a device through traces as shown below. The traces are 1mm wide. All other dimensions are shown below.

Capacitor connection without power planes

Solution:

The connection inductance can be approximated with the use of the rectangular loop equation (http://www.cvel.clemson& ... uct/rectgl.html). The length and width of the rectangle itself is estimated from the current path shown as a red dashed line in the figure above. The length of the equivalent rectangular loop is estimated to be 8 mm plus half of the length of the triangular portion of the current loop (22 mm/2 = 11 mm). The equivalent radius of the wire, a, is 1/4th of the trace width.

Ans. Lconn = 29 nH » 30 nH

Equivalent Loop Areas Equivalent Wire Radius

Example 2: Decoupling Capacitors Connected to Power Planes

Calculate the connection inductance between a capacitor and a device assuming both are connected to power and return planes. The via diameters are 2 mm and the dip package and capacitor are approximately 3 mm above the surface of the power and return plane pair. Neglect the impedance through the power planes.

Capacitor connection without power planes

Solution:
Inductance of the capacitor connection

To calculate the inductance of the decoupling capacitor, Lcap, the formula for the inductance of a 'Rectangular loop above a plane' will be used (http://www.cvel.clemson& ... uct/rectgl.html). The length and width of the equivalent loop for the decoupling capacitor are 10 mm and 3 mm respectively. The equivalent radius of the loop will be the 1 mm radius of the vias.

Lcap = 3.6 nH ~= 4 nH Inductance of the DIP package connection

The inductance of the DIP package connection to the power planes, LDIP, will be calculated with the 'long rectangular loop above a plane' formula (http://www.cvel.clemson& ... uct/g-wire.html). The length of the loop will be 30 mm, the height of the loop will be 3 mm, and the equivalent radius will be approximated as 0.1 mm.

LDIP = 24.6 nH ~= 25 nH

Lconn = Lcap + LDIP = 28.2 nH ~= 28 nH

Example 3: The Inductance of a Decoupling Capacitor Loop

The figure below shows several decoupling capacitor pads on a PCB. The distance between the top layer and the power/return plane pair was 0.02"; all other measurements are shown on the figure. The inductance of the following pad designs was measured with a network analyzer and the results are summarized below.

Various capacitor pad connections to planes

CaseL(nH)
A0.61
B1.32
C2.00
D7.11
E15.7
F10.3

Inductance of Case C:

Method 1: Using the 'rectangular loop above a plane' algorithm
w=0.5", h1=0.02", h=2h1, a=0.025"
ANS: L=3.1 nH ~= 3nH
Method 2: Using the 'long rectangular loop above a plane' algorithm
Length = 0.5", h=0.02", a=0.025"
ANS: L=0.75 nH ~= 1 nH

(Note: Method 2 ignores the inductance due to the portion of the magnetic flux wrapping the vias. This is a reasonable estimate of the inductance due to the flux wrapping the capacitor body only. Flux wrapping the capacitor body dominates in Case A.)

Inductance of Case E:

Method: Using the 'long rectangular loop above a plane' algorithm once for the traces routed to the via, and again for the pad and capacitor package portion of the loop.
Contribution to loop inductance from the traces:
Length =1.0", h=0.02", a= w/4= 0.002"
ANS: Lt=15.24 nH ~= 15 nH
Contribution to the loop inductance from the pad and capacitor package:
Length = 0.5", h=0.02", a=w/4= 0.02"
ANS: Lp/c=0.76 nH ~= 1 nH
Total loop inductance: Lt + Lp/c ~= 16 nH
发表于 2008-1-2 16:46:39 | 显示全部楼层
引用第1楼norman27992007-12-18 12:28发表的“”:
台湾腔啊

怎么看出来台湾腔???  [s:15]

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